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No.4118  Re[2]:\HenKoと \Hen_ko
発言者: tetsu
発言日: 2005 12/11 16:10
発言元: 219.116.100.211
そうですね。失礼いたしました。
TeXファイルとlogファイルは以下の通りです。

〔Texファイル〕
\documentclass[a4paper,fleqn]{jarticle}
\usepackage{emathP,emathMw}
\usepackage[abx]{emathFx}
\let\geqq\abxgeqq
\let\leqq\abxleqq

\begin{document}
\begin{enumerate}
\item 中線定理 \\
         \begin{mawarikomi}{140pt}{%
         \begin{picture}[ul=5mm](9,6)(-2.2,-.8)
         \def\A{(4.5,5)}
         \def\B{(0,0)}
         \def\C{(7,0)}
         \def\H{(4.5,0)}
         \def\M{(3.5,0)}
         \Drawline{\A\B\C\A}
         \Drawline{\A\M}
         \Hasen{\A\H}
         \Put\A(0,8pt)[n]{A}
         \Put\B(-4pt,-8pt)[s]{B}
         \Put\C(0,-8pt)[s]{C}
         \Put\H(-2pt,-8pt)[s]{H}
         \Put\M(-2pt,-8pt)[s]{M}
         \HenKo\M\B{}
         \Bunten\HenKoTyuusin\HenKoTyuuten{0.95}{0.05}\P
         \Bunten\HenKoTyuusin\HenKoTyuuten{1.05}{-0.05}\Q
         \Drawline{\P\Q}
         \HenKo\C\M{}
         \Bunten\HenKoTyuusin\HenKoTyuuten{0.95}{0.05}\P
         \Bunten\HenKoTyuusin\HenKoTyuuten{1.05}{-0.05}\Q
         \Drawline{\P\Q}
         \Tyokkakukigou\C\H\A
         \end{picture}
         }
         \begin{caprm}
         \sankaku{ABC} において $AB>AC$ とする。 \\
         点 A から BC またはその延長線に下ろした垂線を AH,
         辺 BC の中点を M とすると,三平方の定理により, \\
           $AB^2+AC^2$ \\
           $=(BM+MH)^2+AH^2+(MC-MH)^2+AH^2$ \\
           $=(BM+MH)^2+AH^2+(BM-MH)^2+AH^2$ \\
           $=(BM^2+2BM \cdot MH+MH^2)+AH^2+(BM^2-2BM \cdot MH+MH^2)+AH^2$ \\
           $=2(BM^2+HM^2+AH^2)$ $\cdots$ @ \\
         また $HM^2+AH^2=AM^2$ $\cdots$ A \\
         @,Aより \underline{$AB^2+AC^2=2(AM^2+BM^2)$} \\
         これを中線定理という。 \\
         これは $AB \leqq AC$ の場合でも同様に成り立つ。 \\
         \end{caprm}
         \end{mawarikomi}
\item aaa
\end{enumerate}
\end{document}

〔logファイル〕
This is pTeX, Version 3.141592-p3.1.3 (sjis) (Web2C 7.5.2) (format=platex 2003.11.8)  11 DEC 2005 16:04
**text0002.tex
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No file text0002.aux.
\openout1 = `text0002.aux'.

LaTeX Font Info:    Checking defaults for OML/cmm/m/it on input line 7.
LaTeX Font Info:    ... okay on input line 7.
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LaTeX Font Info:    Checking defaults for OT1/cmr/m/n on input line 7.
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LaTeX Font Info:    ... okay on input line 7.


LaTeX Warning: mawarikomi環境を段落途中に配置しました。 on input line 35.


Overfull \hbox (7.08336pt too wide) detected at line 35
\OT1/cmr/m/n/10 B
 []


Overfull \hbox (7.22223pt too wide) detected at line 35
\OT1/cmr/m/n/10 C
 []


Overfull \hbox (7.50002pt too wide) detected at line 35
\OT1/cmr/m/n/10 H
 []


Overfull \hbox (9.16669pt too wide) detected at line 35
\OT1/cmr/m/n/10 M
 []

! Undefined control sequence.
<argument> \xmin 
                 \xunitlength 
l.35          }
               
? 
! Emergency stop.
<argument> \xmin 
                 \xunitlength 
l.35          }
               
End of file on the terminal!

 
Here is how much of TeX's memory you used:
 6754 strings out of 95597
 68469 string characters out of 1191919
 196999 words of memory out of 1500001
 9804 multiletter control sequences out of 10000+50000
 7519 words of font info for 31 fonts, out of 600000 for 2000
 14 hyphenation exceptions out of 2000
 67i,7n,45p,422b,671s stack positions out of 1500i,500n,5000p,200000b,5000s
No pages of output.

\xminと出てくるので「もしや」と思った訳です。
\HenKo\M\B{} 以下を次のように別表記にしました。

〔別表記Texファイル〕
\documentclass[a4paper,fleqn]{jarticle}
\usepackage{emathP,emathMw}
\usepackage[abx]{emathFx}
\let\geqq\abxgeqq
\let\leqq\abxleqq

\begin{document}
\begin{enumerate}
\item 中線定理 \\
         \begin{mawarikomi}{140pt}{%
         \begin{picture}[ul=5mm](9,6)(-2.2,-.8)
         \def\A{(4.5,5)}
         \def\B{(0,0)}
         \def\C{(7,0)}
         \def\H{(4.5,0)}
         \def\M{(3.5,0)}
         \Drawline{\A\B\C\A}
         \Drawline{\A\M}
         \Hasen{\A\H}
         \Put\A(0,8pt)[n]{A}
         \Put\B(-4pt,-8pt)[s]{B}
         \Put\C(0,-8pt)[s]{C}
         \Put\H(-2pt,-8pt)[s]{H}
         \Put\M(-2pt,-8pt)[s]{M}
         \Hen_ko<0.4>\M\B{$m$}
         \Hen_ko<0.4>\C\M{$m$}
         \Tyokkakukigou\C\H\A
         \end{picture}
         }
         \begin{caprm}
         \sankaku{ABC} において $AB>AC$ とする。 \\
         点 A から BC またはその延長線に下ろした垂線を AH,
         辺 BC の中点を M とすると,三平方の定理により, \\
           $AB^2+AC^2$ \\
           $=(BM+MH)^2+AH^2+(MC-MH)^2+AH^2$ \\
           $=(BM+MH)^2+AH^2+(BM-MH)^2+AH^2$ \\
           $=(BM^2+2BM \cdot MH+MH^2)+AH^2+(BM^2-2BM \cdot MH+MH^2)+AH^2$ \\
           $=2(BM^2+HM^2+AH^2)$ $\cdots$ @ \\
         また $HM^2+AH^2=AM^2$ $\cdots$ A \\
         @,Aより \underline{$AB^2+AC^2=2(AM^2+BM^2)$} \\
         これを中線定理という。 \\
         これは $AB \leqq AC$ の場合でも同様に成り立つ。 \\
         \end{caprm}
         \end{mawarikomi}
\item aaa
\end{enumerate}
\end{document}

これだとちゃんと表記されます。

▼関連発言

4111:\HenKoと \Hen_ko [tetsu] 12/10 00:47
 └4113:Re:\HenKoと \Hen_ko [田中徹] 12/10 08:59
  └4118:Re[2]:\HenKoと \Hen_ko [tetsu] 12/11 16:10
   └4119:Re[3]:\HenKoと \Hen_ko [tDB] 12/11 16:42
    └4120:Re[4]:\HenKoと \Hen_ko [田中徹] 12/11 20:51
     └4121:Re[5]:\HenKoと \Hen_ko(解決) [tetsu] 12/11 21:23<-last

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